7p^2+9p-3=0

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Solution for 7p^2+9p-3=0 equation: 



7p^2+9p-3=0

a = 7; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·7·(-3)
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{165}}{2*7}=\frac{-9-\sqrt{165}}{14}
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{165}}{2*7}=\frac{-9+\sqrt{165}}{14}
$

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